Medium
Given an m x n
binary matrix
filled with 0
’s and 1
’s, find the largest square containing only 1
’s and return its area.
Example 1:
Input: matrix = [[“1”,”0”,”1”,”0”,”0”],[“1”,”0”,”1”,”1”,”1”],[“1”,”1”,”1”,”1”,”1”],[“1”,”0”,”0”,”1”,”0”]]
Output: 4
Example 2:
Input: matrix = [[“0”,”1”],[“1”,”0”]]
Output: 1
Example 3:
Input: matrix = [[“0”]]
Output: 0
Constraints:
m == matrix.length
n == matrix[i].length
1 <= m, n <= 300
matrix[i][j]
is '0'
or '1'
.import 'dart:math';
class Solution {
int maximalSquare(List<List<String>> matrix) {
final m = matrix.length;
final n = matrix.first.length;
final List<List<int>> dp = List.generate(m, (_) => List.filled(n, 0));
for (int i = 0; i < m; i++) {
for (int j = 0; j < n; j++) {
if (matrix[i][j] == '1') {
if (i == 0 || j == 0) {
dp[i][j] = 1;
} else {
dp[i][j] = min(dp[i - 1][j], min(dp[i][j - 1], dp[i - 1][j - 1])) + 1;
}
}
}
}
final maxi = dp.map((nums) => nums.reduce(max)).reduce(max);
return maxi * maxi;
}
}