Medium
Given an integer array nums
and an integer k
, return the kth
largest element in the array.
Note that it is the kth
largest element in the sorted order, not the kth
distinct element.
You must solve it in O(n)
time complexity.
Example 1:
Input: nums = [3,2,1,5,6,4], k = 2
Output: 5
Example 2:
Input: nums = [3,2,3,1,2,4,5,5,6], k = 4
Output: 4
Constraints:
1 <= k <= nums.length <= 105
-104 <= nums[i] <= 104
class Solution {
int findKthLargest(List<int> nums, int k) {
int partition(int low, int high, int pivot) {
for (; low <= high; low++, high--) {
for (; nums[low] < pivot; low++);
for (; nums[high] > pivot; high--);
if (low > high) break;
int temp = nums[low];
nums[low] = nums[high];
nums[high] = temp;
}
return low;
}
void quickSort(int low, int high) {
if (low >= high) {
return;
}
int pivot = nums[(low + high) ~/ 2];
int index = partition(low, high, pivot);
quickSort(low, index - 1);
quickSort(index, high);
}
quickSort(0, nums.length - 1);
return nums[nums.length - k];
}
}