Medium
Given an unsorted array of integers nums
, return the length of the longest consecutive elements sequence.
You must write an algorithm that runs in O(n)
time.
Example 1:
Input: nums = [100,4,200,1,3,2]
Output: 4
Explanation: The longest consecutive elements sequence is [1, 2, 3, 4]
. Therefore its length is 4.
Example 2:
Input: nums = [0,3,7,2,5,8,4,6,0,1]
Output: 9
Constraints:
0 <= nums.length <= 105
-109 <= nums[i] <= 109
class Solution {
int longestConsecutive(List<int> nums) {
if (nums.isEmpty) {
return 0;
}
nums.sort(); // Sort the list
int max = -999999999; // Equivalent to Integer.MIN_VALUE in Java
int currentMax = 1;
for (int i = 0; i < nums.length - 1; i++) {
if (nums[i + 1] == nums[i] + 1) {
currentMax += 1;
continue;
}
if (nums[i + 1] == nums[i]) {
continue;
}
// Start of a new sequence
max = maxVal(max, currentMax);
currentMax = 1;
}
return maxVal(max, currentMax);
}
int maxVal(int a, int b) => a > b ? a : b; // Utility function for max
}