LeetCode-in-Dart
5. Longest Palindromic Substring
Medium
Given a string s, return the longest palindromic substring in s.
Example 1:
Input: s = “babad”
Output: “bab” Note: “aba” is also a valid answer.
Example 2:
Input: s = “cbbd”
Output: “bb”
Example 3:
Input: s = “a”
Output: “a”
Example 4:
Input: s = “ac”
Output: “a”
Constraints:
1 <= s.length <= 1000sconsist of only digits and English letters.
Solution
class Solution {
String longestPalindrome(String s) {
List<String> newStr = List.filled(s.length * 2 + 1, '#');
for (int i = 0; i < s.length; i++) {
newStr[2 * i + 1] = s[i];
newStr[2 * i + 2] = '#';
}
List<int> dp = List.filled(newStr.length, 0);
int friendCenter = 0;
int friendRadius = 0;
int lpsCenter = 0;
int lpsRadius = 0;
for (int i = 0; i < newStr.length; i++) {
dp[i] = (friendCenter + friendRadius > i)
? (dp[friendCenter * 2 - i] < (friendCenter + friendRadius) - i
? dp[friendCenter * 2 - i]
: (friendCenter + friendRadius) - i)
: 1;
while (i + dp[i] < newStr.length &&
i - dp[i] >= 0 &&
newStr[i + dp[i]] == newStr[i - dp[i]]) {
dp[i]++;
}
if (friendCenter + friendRadius < i + dp[i]) {
friendCenter = i;
friendRadius = dp[i];
}
if (lpsRadius < dp[i]) {
lpsCenter = i;
lpsRadius = dp[i];
}
}
return s.substring(
(lpsCenter - lpsRadius + 1) ~/ 2, (lpsCenter + lpsRadius - 1) ~/ 2);
}
}